
组合数学——容斥定理
Alex_McAvoy
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组合数学 —— 容斥定理
【概述】容斥原理是一种较常用的计数方法,其基本思想是:先不考虑重叠的情况,把包含于某内容中的所有对象的数目先计算出来,然后再把计数时重复计算的数目排斥出去,使得计算的结果既无遗漏又无重复。容斥原理核心的计数规则可以记为一句话:奇加偶减假设被计数的有 A、B、C 三类,那么,A、B、C 类元素个数总和 = A 类元素个数 + B类元素个数 + C类元素个数 - 既是 A 又是 B 的元素...原创 2018-08-13 17:31:34 · 7968 阅读 · 0 评论 -
How many integers can you find(HDU-1796)
Problem DescriptionNow you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divided exactly by any integers in the set. For example,...原创 2018-08-12 21:22:05 · 302 阅读 · 2 评论 -
February 29(LightOJ-1414)
Problem DescriptionIt is 2012, and it's a leap year. So there is a "February 29" in this year, which is called leap day. Interesting thing is the infant who will born in this February 29, will get ...原创 2019-02-13 23:25:33 · 437 阅读 · 0 评论 -
Co-prime(HDU-4135)
Problem DescriptionGiven a number N, you are asked to count the number of integers between A and B inclusive which are relatively prime to N.Two integers are said to be co-prime or relatively prim...原创 2018-08-12 21:19:56 · 496 阅读 · 0 评论 -
Helping Cicada(LightOJ-1117)
Problem DescriptionCicada is an insect with large transparent eyes and well-veined wings similar to the "jar flies". The insects are thought to have evolved 1.8 million years ago during the Pleisto...原创 2019-03-26 15:46:03 · 447 阅读 · 0 评论 -
跳蚤(POJ-1091)
Problem DescriptionZ城市居住着很多只跳蚤。在Z城市周六生活频道有一个娱乐节目。一只跳蚤将被请上一个高空钢丝的正中央。钢丝很长,可以看作是无限长。节目主持人会给该跳蚤发一张卡片。卡片上写有N+1个自然数。其中最后一个是M,而前N个数都不超过M,卡片上允许有相同的数字。跳蚤每次可以从卡片上任意选择一个自然数S,然后向左,或向右跳S个单位长度。而他最终的任务是跳到距离他左边一个...原创 2018-08-14 17:20:54 · 1341 阅读 · 0 评论 -
矩形并的面积(51Nod-2488)
题目在二维平面上,给定两个矩形,满足矩形的每条边分别和坐标轴平行,求这个两个矩形的并的面积。即它们重叠在一起的总的面积。输入8个数,分别表示第一个矩形左下角坐标为(A,B),右上角坐标为(C,D);第二个矩形左下角坐标为(E,F),右上角坐标为(G,H)。保证A<C,B<D,E<G,F<H。保证所有数的绝对值不超过2*10^9,矩形并的面积≤2*10^9。...原创 2019-04-29 20:02:59 · 736 阅读 · 5 评论