优化:在划分的时候使用左右同时移动,找到i大于基准点的数和j小于基准点的数(在i<j)的情况下,互换位置,到i>=j,查看r[i]的大小,大于基准点说明i-1为想要位置,否则就是i。
#include<iostream>
using namespace std;
int Partition2(int r[], int low, int high)
{
int i = low, j = high, pivot = r[low];
while (i < j)
{
while (i<j&&r[j]>pivot) j--;
while (i < j&&r[i] <= pivot) i++;
if (i < j)
{
int t = r[j];
r[j++] = r[i];
r[i++] = t;
}
}
if (r[i] > pivot)
{
int t = r[low];
r[low] = r[i-1];
r[i-1] = t;
return i - 1;
}
else
{
int t = r[low];
r[low] = r[i];
r[i] = t;
return i;
}
}
void QuickSort(int r[], int low, int high)
{
if (low < high)
{
int mid = Partition2(r, low, high);
QuickSort(r, low, mid-1);
QuickSort(r, mid + 1, high);
}
}
int main() {
int r[5] = {1,5,3,4,2};
QuickSort(r, 0, 4);
for (int i = 0; i < 5; i++)
{
cout << r[i] << " ";
}
return 0;
}