源码附上:
#include <iostream>
#include <math.h>
using namespace std;
long long S[1001];
int main()
{
int n;
cin>>n;
int i,j;
for(i=0;i<n;i++)
{
cin>>S[i];
if(S[i]==2||S[i]==3)
{
cout<<"Yes"<<endl;
continue;
}
for(j=2;j<=sqrt(S[i]);j++)
{
if(S[i]%j==0)
{
break;
}
}
if(j>sqrt(S[i]))
{
cout<<"Yes"<<endl;
}
else
{
cout<<"No"<<endl;
}
}
return 0;
}