Python内置函数

a=[1,2,3,4,5]
print(len(a)) 
print(a.__len__())

x=a[1]
print(x)
print(a.__getitem__(1))

a[1]=6
print(a[1])
a.__setitem__(1,7)
print(a)

del a[1]
print(a)

a.__delitem__(0)
print(a)

print(3 in a)
print(a.__contains__(3))

输出：

5
5
2
2
6
[1, 7, 3, 4, 5]
[1, 3, 4, 5]
[3, 4, 5]
True
True