思路:Tarjan算法模板题。
#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<vector>
#include<stack>
const int MAXN=10000+10;
using namespace std;
vector<int>mp[MAXN];
stack<int>S;
int n,m;
int _count;
int cnt;
bool mark[MAXN];
int dfn[MAXN];
int low[MAXN];
//求强连通分量tarjan
void Tarjan(int u){
dfn[u]=low[u]=++cnt;
mark[u]=true;
S.push(u);
for(int i=0;i<mp[u].size();i++){
int v=mp[u][i];
if(dfn[v]==0){
Tarjan(v);
low[u]=min(low[u],low[v]);
}else if(mark[v]&&dfn[v]<low[u]){
low[u]=dfn[v];
}
}
if(low[u]==dfn[u]){
_count++;
int v;
do{
v=S.top();
S.pop();
mark[v]=false;
}while(u!=v);
}
}
int main(){
while(~scanf("%d%d",&n,&m)){
if(n==0&&m==0)break;
for(int i=1;i<=n;i++)mp[i].clear();
for(int i=1;i<=m;i++){
int x,y;
scanf("%d%d",&x,&y);
mp[x].push_back(y);
}
memset(mark,false,sizeof(mark));
memset(dfn,0,sizeof(dfn));
memset(low,0,sizeof(low));
_count=0;
cnt=0;
for(int i=1;i<=n;i++){
if(dfn[i]==0){
Tarjan(i);
}
}
if(_count>1){
printf("No\n");
}else
printf("Yes\n");
}
return 0;
}