LeetCode 4: Median of Two Sorted Arrays

Median of Two Sorted Arrays

There are two sorted arrays nums1 and nums2 of size m and n respectively.

Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).

You may assume nums1 and nums2 cannot be both empty.

Example 1:

nums1 = [1, 3]
nums2 = [2]

The median is 2.0

Example 2:

nums1 = [1, 2]
nums2 = [3, 4]

The median is (2 + 3)/2 = 2.5

my solution:

class Solution {
    public double findMedianSortedArrays(int[] nums1, int[] nums2) {
        int len1 = nums1.length;
        int len2 = nums2.length;
        int totalNum = len1 + len2;
        int i = 0, j = 0; // 两个数组的游标
        int value1=0, value2=0, currentValue=0; //随便初始化一下

        while(true){

            if(i == len1){
                currentValue = nums2[j++];    
            }else if(j == len2){
                currentValue = nums1[i++];
            }else
                currentValue = (nums1[i]>nums2[j])?nums2[j++]:nums1[i++];

            if(i+j-1 == totalNum/2-1)
                value1 = currentValue; //当总数为偶数时需要用到
            if(i+j-1 == totalNum/2){
                value2 = currentValue; //总数为奇数时的中位数
                break;
            }
        }       
        return totalNum % 2 == 0?(value1+value2)/2.0:value2;
    }
}