#include"iostream"
using namespace std;
long long mul1(long long a,long long b,long long mod)
{
long double x;
long long c;
long long r;
if (a >= mod) a %= mod;
if (b >= mod) b %= mod;
x = a;
c = x * b / mod;
r = (a * b - c * mod) % mod;
return r < 0 ? r + mod : r;
}
long long mul2(long long a,long long b,long long mod)
{
a%=mod;
b%=mod;
long long res=0,base=a;
while(b)
{
if(b&1)res=(res+base)%mod;
base=(base*2)%mod;
b>>=1;
}
return res;
}
long long mul3(long long a,long long b,long long mod)///tao shen de gong shi
{
return (a*b-(long long)(a/(long double) mod * b + 1e-3)* mod + mod) % mod;
}
int main()
{
long long a=1e18+7,b=1e17+38,mod=1e18+79;
// for(int i=1;i<=100000000;i++)
cout<<mul1(a,b,mod)<<"\n";
cout<<mul2(a,b,mod)<<"\n";
cout<<mul3(a,b,mod)<<"\n";
}
模乘
最新推荐文章于 2021-12-15 00:02:38 发布