Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
public static int getHeight(TreeNode root) {
if (root == null) {
return 0;
}
int left = getHeight(root.left);
int right = getHeight(root.right);
if (left == -1 || right == -1) {
return -1;
}
if (Math.abs(left - right) > 1) {
return -1;
}
return Math.max(left, right) + 1;
}
public boolean isBalanced(TreeNode root) {
return (getHeight(root) != -1);
}
本文介绍了一种算法,用于确定二叉树是否为高度平衡的。通过递归计算每个节点的左右子树深度,并确保任意节点的左右子树深度之差不超过1,实现了这一功能。
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