Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +
, -
, *
, /
. Each operand may be an integer or another expression.
Some examples:
["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9 ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6用stack解题。遍历字符串数组,如果是符号,从stack里弹出两个数进行对应的计算,如果是数字,转化成对应值之后入栈,最后结果返回stack的仅存的一个数。代码如下:
public class Solution {
public int evalRPN(String[] tokens) {
if(tokens.length == 0) {
return 0;
}
Stack<Integer> stack = new Stack<Integer>();
int num1 = 0, num2 = 0;
for (String str: tokens) {
if (str.equals("+")) {
num2 = stack.pop();
num1 = stack.pop();
stack.push(num1 + num2);
} else if (str.equals("-")) {
num2 = stack.pop();
num1 = stack.pop();
stack.push(num1 - num2);
} else if (str.equals("*")) {
num2 = stack.pop();
num1 = stack.pop();
stack.push(num1 * num2);
} else if (str.equals("/")) {
num2 = stack.pop();
num1 = stack.pop();
stack.push(num1 / num2);
} else {
stack.push(Integer.parseInt(str));
}
}
return stack.pop();
}
}