这个题根据它所给的计算式,二分i,然后枚举j进行统计,二分套二分吧
代码:
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
long long n,m;
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
scanf("%I64d%I64d",&n,&m);
long long l=-100000*n,r=n*n+100000*n+n*n+n*n;
long long ans=0;
while(l<=r)
{
long long mid=(l+r)>>1;
long long cnt=0;
for(long long j=1;j<=n;j++)
{
long long sl=1,sr=n;
long long scnt=0;
while(sl<=sr)
{
long long smid=(sl+sr)>>1;
long long val=smid*smid+100000*smid+j*j-100000*j+smid*j;
if(val<=mid)
{
scnt=smid;
sl=smid+1;
}
else
sr=smid-1;
}
cnt+=scnt;
}
if(cnt>=m)
{
ans=mid;
r=mid-1;
}
else
l=mid+1;
}
printf("%I64d\n",ans);
}
return 0;
}