Problem Description
There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).
Input
Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).
Output
Print the word “yes” if 3 divide evenly into F(n).
Print the word “no” if not.
Sample Input
0
1
2
3
4
5
Sample Output
no
no
yes
no
no
no
Code
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int x = sc.nextInt();
switch (x % 4) {
case 0:
case 1:
case 3:
System.out.println("no");
break;
case 2:
System.out.println("yes");
break;
default:
break;
}
}
sc.close();
}
}
本文介绍了一种特殊的斐波那契数列,其中F(0)=7且F(1)=11,并通过Java程序判断该数列中任意项是否能被3整除。输入为一系列整数n,输出表明F(n)是否可以被3整除。
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