HDU 1026 迷宫战斗问题 使用了优先队列

本文介绍了一种使用优先队列实现的迷宫寻路算法,通过广度优先搜索(BFS)来寻找从起点到终点的最短路径,并考虑了特殊情况下需要进行战斗的时间消耗。该算法还记录了到达每个节点的路径。

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#include <iostream>
#include <queue>
#include <stdio.h>
#include <string.h>
using namespace std;

const int MAXN = 100;
struct node
{
	int x, y;
	int time;
	friend bool operator <(node a, node b)  //time小的优先级高
	{
		return a.time > b.time;
	}
};

priority_queue<node> que; //优先队列
struct cmp
{
	int nx, ny; //记录前驱
	char c;
}map[MAXN][MAXN];

int n, m;
int fight[MAXN][MAXN], mark[MAXN][MAXN];

int bfs()
{
	int k;
	int dir[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
	node now, next;
	while(!que.empty()) 
		que.pop();
	now.x = n -  1;
	now.y = m - 1;
	if(map[now.x][now.y].c >= '1' && map[now.x][now.y].c <= '9')
	{
		now.time = map[n - 1][m - 1].c - '0';
		fight[now.x][now.y] =  map[now.x][now.y].c - '0';
	}
	else 
		now.time = 0;

	que.push(now);
	while(!que.empty())
	{
		now = que.top();
		que.pop();
		if(now.x ==0 && now.y == 0)
			return now.time;
		for(k = 0; k < 4; k++)
		{
			next.x = now.x + dir[k][0];
			next.y = now.y + dir[k][1];
			if(next.x >= 0 && next.x < n && next.y >= 0 && next.y < m && !mark[next.x][next.y] && map[next.x][next.y].c != 'X')
			{
				if(map[next.x][next.y].c >= '1' && map[next.x][next.y].c <= '9')
				{
					next.time = now.time + map[next.x][next.y].c - '0' + 1;
					fight[next.x][next.y] = map[next.x][next.y].c - '0';
				}
				else
					next.time = now.time + 1;
				que.push(next);
				map[next.x][next.y].nx = now.x;
				map[next.x][next.y].ny = now.y;
				mark[next.x][next.y] = 1;
			}
		}
	}
	return -1;
}


int main()
{
	while(scanf("%d%d", &n, &m) != EOF)
	{
		for(int i = 0; i < n; i++)
		{
			for(int j = 0; j < m; j++)
			{
				scanf(" %c", &map[i][j].c); //前面的空格很关键,或者直接用cin
				//cin >> map[i][j].c;
				mark[i][j] = fight[i][j] = 0;
			}
		}
		for(int i = 0; i < n; i++)
		{
			for(int j = 0; j < m; j++)
			{
				cout << map[i][j].c ;
			}
			cout << endl;
		}
		mark[n - 1][m - 1] = 1;
		int flag = bfs();
		if(flag != -1)
		{
			printf("It takes %d seconds to reach the target position, let me show you the way.\n",flag);
			int sec = 1, x = 0, y = 0;
			int tx, ty;
			while(sec != flag + 1)
			{
				printf("%ds:(%d,%d)->(%d,%d)\n",sec++,x,y,map[x][y].nx,map[x][y].ny);
				for(int i = 0; i < fight[map[x][y].nx][map[x][y].ny]; i++)
					printf("%ds:FIGHT AT (%d,%d)\n",sec++,map[x][y].nx,map[x][y].ny);
				tx = map[x][y].nx;
				ty = map[x][y].ny;
				x = tx;
				y = ty;
			}
		}
		else
			printf("God please help our poor hero.\n");
		printf("FINISH\n");
	}
	return 0;
}

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