Codeforces Round #163 (Div. 2) / 226A Stones on the Table (字符串处理)

A. Stones on the Table

http://codeforces.com/problemset/problem/266/A

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.

Input

The first line contains integer n (1 ≤ n ≤ 50) — the number of stones on the table.

The next line contains string s, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to n from left to right. Then the i-th character s equals "R", if the i-th stone is red, "G", if it's green and "B", if it's blue.

Output

Print a single integer — the answer to the problem.

Sample test(s)

input

3
RRG

output

1

input

5
RRRRR

output

4

input

4
BRBG

output

0

题意：一列的石子有三种颜色，取出x个，剩下的石子相邻间颜色不同，求min(x)。

完整代码：

/*30ms,0KB*/

#include <cstdio>

int main()
{
	int n, count = 0;
	scanf("%d", &n);
	getchar();
	char now = getchar(), ch;
	while (--n)
	{
		ch = getchar();
		if (ch == now)
			++count;
		else
			now = ch;
	}
	printf("%d", count);
	return 0;
}