−2−1−−−√12((−1)5/6tan−1((−1)5/12(2+(1−i3√)tan(x2))23√4)+tan−1((−1)7/12(2+(1+i3√)tan(x2))23√4))33−−√4+C=∫1−sin(x)1−sin3(x)dx −2−1−−−√12((−1)5/6tan−1((−1)5/12(2+(1−i3√)tan(x2))23√4)+tan−1((−1)7/12(2+(1+i3√)tan(x2))23√4))33/4