uva 11384 正整数序列

Dexter is tired of Dee Dee. So he decided to keep Dee Dee busy in a game. The game he planned for
her is quite easy to play but not easy to win at least not for Dee Dee. But Dexter does not have time
to spend on this silly task, so he wants your help.
There will be a button, when it will be pushed a random number N will be chosen by computer.
Then on screen there will be numbers from 1 to N. Dee Dee can choose any number of numbers from
the numbers on the screen, and then she will command computer to subtract a positive number chosen
by her (not necessarily on screen) from the selected numbers. Her objective will be to make all the
numbers 0.
For example if N = 3, then on screen there will be 3 numbers on screen: 1, 2, 3. Say she now selects
1 and 2. Commands to subtract 1, then the numbers on the screen will be: 0, 1, 3. Then she selects 1
and 3 and commands to subtract 1. Now the numbers are 0, 0, 2. Now she subtracts 2 from 2 and all
the numbers become 0.
Dexter is not so dumb to understand that this can be done very easily, so to make a twist he will
give a limit L for each N and surely L will be as minimum as possible so that it is still possible to win
within L moves. But Dexter does not have time to think how to determine L for each N, so he asks
you to write a code which will take N as input and give L as output.
Input
Input consists of several lines each with N such that 1 ≤ N ≤ 1, 000, 000, 000. Input will be terminated
by end of file.
Output
For each N output L in separate lines.
Sample Input
1
2
3
Sample Output
1
2
2

题目大意为给定一个序列 1到n ,用最少的操作次数把序列所有数都变成0
每次操作从序列中选取一个或者多个数,同时减去一个整数。
输出最少操作次数。

简单的数学问题。
一种类似与折半的处理方法

比如 1 2 3 4 5 6 变成 1 2 3 0 1 2 这个序列 等价于1 2 3
再比如说 1 2 3 4 5 6 7 8 变成 1 2 3 4 0 1 2 3 等价于 1 2 3 4
1 2 3 4 变成 1 2 0 1 等价于1 2
1 2 编程 1 0 等价于 1
然后 找下规律
代码太简单不想打

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值