HDOJ(递归)——1012.u Calculate e

Problem Description

A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

Sample Output

n e

---

0 1
1 2
2 2.5
3 2.666666667
4 2.708333333

题目大意：

给定e的计算公式，按格式输出n为0-9e的结果。

题目解析：

简单递归可以计算出e的值，要注意输出格式。

具体代码：

#include<iostream>
#