hdoj1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 32916    Accepted Submission(s): 14786

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
代码如下：（本题的题意和格式相信看了代码一目了然，打印的就是数字！！！）
#include <stdio.h>
int main()
{
printf("n e\n");
printf("- -----------\n");
printf("0 1\n");
printf("1 2\n");
printf("2 2.5\n");
int a;
double sum=2.5,fe=0.5;
for(int i=3;i<=9;i++)
{
fe=fe*(1.0/i);
sum+=fe;
printf("%d %.9lf\n",i,sum);
}
return 0;
}