您熟悉在时钟的正边缘或负边缘触发的。在时钟的两个边沿触发双边沿触发触发器。但是,FPGA 没有双边触发触发器,并且始终不接受 @(posedge clk 或 negedge clk) 作为敏感度列表。

You're familiar with flip-flops that are triggered on the positive edge of the clock, or negative edge of the clock. A dual-edge triggered flip-flop is triggered on both edges of the clock. However, FPGAs don't have dual-edge triggered flip-flops, and always @(posedge clk or negedge clk) is not accepted as a legal sensitivity list.
也就是说,对输入的信号延时半个时钟周期

module top_module (
input clk,
input d,
output q
);
wire clk_reg;
reg d1;
reg d2;
/*
assign q = clk? d1 : d2;
always@ (posedge clk ) begin
d1 <= d;
end
always@ (negedge clk ) begin
d2 <= d;
end
*/
// After posedge clk, p changes to d^n. Thus q = (p^n) = (d^n^n) = d.
// After negedge clk, n changes to d^p. Thus q = (p^n) = (p^d^p) = d.
assign q = d1 ^ d2;
always@ (posedge clk ) begin
d1 <= d ^ d2;
end
always@ (negedge clk ) begin
d2 <= d ^ d1;
end
endmodule
FPGA中实现双边触发效果的技巧
文章讨论了如何在FPGA中模拟双边触发器的效果,由于FPGA不直接支持双边触发,通过在正时钟边缘和负时钟边缘分别更新寄存器d1和d2的值,然后用异或门结合这两个寄存器的值来实现输入信号d的即时更新。这样,在每个时钟周期的两个边沿,都能得到正确的输出q。
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