You are given an integer array nums. You are initially positioned at the array's first index, and each element in the array represents your maximum jump length at that position.
Return true if you can reach the last index, or false otherwise.
Example 1:
Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
Example 2:
Input: nums = [3,2,1,0,4] Output: false Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index.
class Solution {
public:
bool canJump(vector<int>& nums) {
if(nums.size()==1) return true;
int k = 0;
for(int i = 0;i <= k;i++){
k = max(k ,i + nums[i]);
if(k >= nums.size() - 1)
return true;
}
return false;
}
};
文章探讨了如何利用给定数组中的最大跳跃长度判断是否能从起始位置跳到最后。Solution类中的canJump函数实现了解决策略。
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