给定一个 m x n 的矩阵,如果一个元素为 0 ,则将其所在行和列的所有元素都设为 0 。请使用 原地 算法。
示例 1:
输入:matrix = [[1,1,1],[1,0,1],[1,1,1]]
输出:[[1,0,1],[0,0,0],[1,0,1]]
示例 2:
输入:matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
输出:[[0,0,0,0],[0,4,5,0],[0,3,1,0]]
class Solution:
def setZeroes(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
col = False
row = False
for j in range(len(matrix[0])):
if matrix[0][j] == 0:
row = True
break
for i in range(len(matrix)):
if matrix[i][0] == 0:
col = True
break
for i in range(1, len(matrix)):
for j in range(1, len(matrix[0])):
if matrix[i][j] == 0:
matrix[i][0] = 0
matrix[0][j] = 0
for i in range(1, len(matrix)):
for j in range(1, len(matrix[0])):
if matrix[i][0] == 0 or matrix[0][j] == 0:
matrix[i][j] = 0
if row:
for j in range(len(matrix[0])):
matrix[0][j] = 0
if col:
for i in range(len(matrix)):
matrix[i][0] = 0