难度:2
Given a collection of numbers, return all possible permutations.
For example,
[1,2,3]
have the following permutations:
[1,2,3]
, [1,3,2]
, [2,1,3]
, [2,3,1]
, [3,1,2]
,
and [3,2,1]
.
class Solution
{
public:
vector<vector<int> > ans;
vector<int>tmp;
vector<bool>flag;
vector<int>a;
int n;
void dfs(int index)
{
if(index == n) {ans.push_back(tmp);return;}
for(int i=0;i<n;i++)
{
if(flag[i]) continue;
tmp.push_back(a[i]);
flag[i]=true;
dfs(index+1);
tmp.pop_back();
flag[i]=false;
}
}
vector<vector<int> > permute(vector<int> &num)
{
ans.clear();
tmp.clear();
a.assign(num.begin(),num.end());
n=num.size();
flag.assign(n,false);
dfs(0);
return ans;
}
};