Increase and Copy

该博客详细介绍了如何使用C++解决在线编程竞赛Codeforces中的一道题目,涉及计算平方根整数的累加和,直到和大于输入数值。通过两篇参考代码示例,展示了如何通过循环计算找到答案,并输出结果。

题目:
https://codeforces.com/contest/1426/problem/C
借鉴学习代码:
https://blog.youkuaiyun.com/hzf0701/article/details/108856358
https://blog.youkuaiyun.com/TopTom1234/article/details/108858008

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main()
{
    int t;
    ll n;
    cin>>t;
    while(t--){
        cin>>n;
        int x = sqrt(n);
        int ans = x-1;
        ll sum = x;
        while(sum<n){
            sum+=x;
            ans++;
          }
        cout<<ans<<endl;
    }
    return 0;
}

A piece of paper contains an array of n integers a1, a2, ..., an. Your task is to find a number that occurs the maximum number of times in this array. However, before looking for such number, you are allowed to perform not more than k following operations — choose an arbitrary element from the array and add 1 to it. In other words, you are allowed to increase some array element by 1 no more than k times (you are allowed to increase the same element of the array multiple times). Your task is to find the maximum number of occurrences of some number in the array after performing no more than k allowed operations. If there are several such numbers, your task is to find the minimum one. Input The first line contains two integers n and k (1 ≤ n ≤ 105; 0 ≤ k ≤ 109) — the number of elements in the array and the number of operations you are allowed to perform, correspondingly. The third line contains a sequence of n integers a1, a2, ..., an (|ai| ≤ 109) — the initial array. The numbers in the lines are separated by single spaces. Output In a single line print two numbers — the maximum number of occurrences of some number in the array after at most k allowed operations are performed, and the minimum number that reaches the given maximum. Separate the printed numbers by whitespaces. Examples Inputcopy Outputcopy 5 3 6 3 4 0 2 3 4 Inputcopy Outputcopy 3 4 5 5 5 3 5 Inputcopy Outputcopy 5 3 3 1 2 2 1 4 2 Note In the first sample your task is to increase the second element of the array once and increase the fifth element of the array twice. Thus, we get sequence 6, 4, 4, 0, 4, where number 4 occurs 3 times. In the second sample you don't need to perform a single operation or increase each element by one. If we do nothing, we get array 5, 5, 5, if we increase each by one, we get 6, 6, 6. In both cases the maximum number of occurrences equals 3. So we should do nothing, as number 5 is less than number 6. In the third sample we should increase the second array element once and the fifth element once. Thus, we get sequence 3, 2, 2, 2, 2, where number 2 occurs 4 times.讲解这道题
09-21
基于遗传算法的新的异构分布式系统任务调度算法研究(Matlab代码实现)内容概要:本文档围绕基于遗传算法的异构分布式系统任务调度算法展开研究,重点介绍了一种结合遗传算法的新颖优化方法,并通过Matlab代码实现验证其在复杂调度问题中的有效性。文中还涵盖了多种智能优化算法在生产调度、经济调度、车间调度、无人机路径规划、微电网优化等领域的应用案例,展示了从理论建模到仿真实现的完整流程。此外,文档系统梳理了智能优化、机器学习、路径规划、电力系统管理等多个科研方向的技术体系与实际应用场景,强调“借力”工具与创新思维在科研中的重要性。; 适合人群:具备一定Matlab编程基础,从事智能优化、自动化、电力系统、控制工程等相关领域研究的研究生及科研人员,尤其适合正在开展调度优化、路径规划或算法改进类课题的研究者; 使用场景及目标:①学习遗传算法及其他智能优化算法(如粒子群、蜣螂优化、NSGA等)在任务调度中的设计与实现;②掌握Matlab/Simulink在科研仿真中的综合应用;③获取多领域(如微电网、无人机、车间调度)的算法复现与创新思路; 阅读建议:建议按目录顺序系统浏览,重点关注算法原理与代码实现的对应关系,结合提供的网盘资源下载完整代码进行调试与复现,同时注重从已有案例中提炼可迁移的科研方法与创新路径。
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