题意:给一个区间,有n次染色操作,每次将[x1, x2]染为c,求最后每种颜色各有多少线段可以看到。
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<queue>
#include<set>
#include<vector>
using namespace std;
#define INF 0x3f3f3f3f
#define eps 1e-10
typedef long long LL;
const int MAXN = 1e5+5;
const int mod = 998244353;
LL st[MAXN << 2];
int vis[MAXN];
void pushdown(int o)
{
if(st[o] != -1)
{
st[o << 1] = st[o];
st[o << 1 | 1] = st[o];
st[o] = -1;
return;
}
}
void update(int o,int l,int r,int ql,int qr,int c)
{
if(ql <= l && r <= qr) {
st[o] = c;
return;
}
else {
if(st[o] != c){
pushdown(o);
int m = (l + r) >> 1;
if(ql <= m) update(o << 1,l,m,ql,qr,c);
if(m + 1 <= qr) update(o << 1 | 1,m + 1,r,ql,qr,c);
}
else return;
}
}
int last;
void query(int o,int l,int r)
{
if(l == r)
{
if(st[o] != -1 && st[o] != last)
vis[st[o]]++;
last = st[o];
return;
}
pushdown(o);
int m = (l + r) >> 1;
query(o << 1,l,m);
query(o << 1 | 1,m + 1,r);
}
int main()
{
int n;
while(~scanf("%d",&n))
{
memset(st,-1,sizeof st);
while(n--)
{
int x,y,c;
scanf("%d %d %d",&x,&y,&c);
update(1,1,8000,x + 1,y,c);
}
memset(vis,0,sizeof vis);
last = -1;
query(1,1,8000);
for(int i = 0; i <= 8000; i++)
if(vis[i])
printf("%d %d\n",i,vis[i]);
printf("\n");
}
}