#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
/*
* 最小树形图
* int型
* 复杂度O(NM)
* 点从0开始
*/
const int INF = 0x3f3f3f3f;
const int MAXN = 1010;
const int MAXM = 40010;
struct Edge
{
int u,v;
double cost;
};
struct Point{
double x, y;
double GetDist(const Point &p) const{
return sqrt((x - p.x) * (x - p.x) + (y - p.y) * (y - p.y));
}
};
Point p[MAXN];
Edge edge[MAXM];
int pre[MAXN],id[MAXN],visit[MAXN];
double in[MAXN];
//root 根节点,n点个数,m边条数,edge边数组
double zhuliu(int root,int n,int m,Edge edge[])
{
double res = 0;
int u,v;
while(1)
{
for(int i = 0;i < n;i++)
in[i] = INF;
for(int i = 0;i < m;i++)
if(/*edge[i].u != edge[i].v && */edge[i].cost < in[edge[i].v])
{
pre[edge[i].v] = edge[i].u;
in[edge[i].v] = edge[i].cost;
}
for(int i = 0;i < n;i++)
if(i != root && in[i] == INF)
return -1.0;//不存在最小树形图
int tn = 0;
memset(id,-1,sizeof(id));
memset(visit,-1,sizeof(visit));
in[root] = 0;
for(int i = 0;i < n;i++)
{
res += in[i];
v = i;
while( /*visit[v] != i*/ visit[v] == -1 /*&& id[v] == -1 */ && v != root)
{
visit[v] = i;
v = pre[v];
}
if( v != root && visit[v] == i /*id[v] == -1*/)
{
for(int u = pre[v]; u != v ;u = pre[u])
id[u] = tn;
id[v] = tn++;
}
}
if(tn == 0)break;//没有有向环
for(int i = 0;i < n;i++)
if(id[i] == -1)
id[i] = tn++;
for(int i = 0;i < m;)
{
v = edge[i].v;
edge[i].u = id[edge[i].u];
edge[i].v = id[edge[i].v];
if(edge[i].u != edge[i].v)
edge[i++].cost -= in[v];
else
swap(edge[i],edge[--m]);
}
n = tn;
root = id[root];
}
return res;
}
double g[MAXN][MAXN];
int main()
{
int n,m;
while(~scanf("%d%d",&n,&m)){
for(int i = 0;i < n;i++)
for(int j = 0;j < n;j++)
g[i][j] = INF;
for(int i = 0; i < n; i++){
scanf("%lf %lf", &p[i].x, &p[i].y);
}
int u,v;
while(m--)
{
scanf("%d%d",&u,&v);
if(u == v)continue;
u -= 1; v -= 1;
g[u][v] = min(g[u][v],p[u].GetDist(p[v]));
}
int L = 0;
for(int i = 0;i < n;i++)
for(int j = 0;j < n;j++)
if(g[i][j] < INF)
{
edge[L].u = i;
edge[L].v = j;
edge[L++].cost = g[i][j];
}
double ans = zhuliu(0,n,L,edge);
if(ans == -1.0)printf("poor snoopy\n");
else printf("%.2f\n",ans);
}
return 0;
}
【模板】【最小树形图】
最新推荐文章于 2024-07-13 22:06:43 发布