ACM之路

Transfer waterTime Limit: 5000/3000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 4420    Accepted Submission(s): 1567Problem DescriptionXiaoA lives

Minimum CostTime Limit: 4000MS Memory Limit: 65536KTotal Submissions: 15057 Accepted: 5176DescriptionDearboy, a goods victualer, now comes to a big problem, and

FoodTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4105    Accepted Submission(s): 1365Problem Description　　You, a part-time di

上界改容量，下界先流走。 U -> V之间添加一条 cap - down的边S->U 为U多出来的入的下界- 出的下界V -> T 为V多出来的出的下界-入的下界Max_Flow MF;int n,m;const int maxn = 210;const int maxm = 40010;int a[maxn];int id[maxm];int up[maxm]

int n,m; Max_Flow MF;int main(){ freopen("in.txt","r",stdin); //freopen("out.txt","w",stdout); while(scanf("%d%d",&n,&m) != EOF) { int S,T; scanf("%d%d",&S,&T); MF.Init(2*n+2,S,T

Leapin' LizardsTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1752    Accepted Submission(s): 717Problem DescriptionYour platoo

Max_Flow MF;int n,m;int main(){ while(scanf("%d%d",&n,&m) != EOF) { if(n == 0 && m == 0) break; MF.Init(n+5,1,n); int u,v,w; for(int i=0;i<m;i++) { scanf("%d%d%d",&u,&v,&w); MF

Air RaidTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4154    Accepted Submission(s): 2758Problem DescriptionConsider a town w

Fire NetTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8207    Accepted Submission(s): 4704Problem DescriptionSuppose that we h

Island TransportTime Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 6668    Accepted Submission(s): 2091Problem Description　　In th