Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
Accepted
349,504
Submissions
811,345
标准写法:
class Solution:
def sortColors(self, nums: List[int]) -> None:
l,cur,r = 0,0,len(nums)-1
while (cur <= r):
if (nums[cur] == 0):
nums[l],nums[cur]=nums[cur],nums[l]
l,cur = l+1,cur+1
elif (nums[cur] == 2):
nums[r],nums[cur]=nums[cur],nums[r]
r -= 1
else:
cur += 1

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