使用python与.exe文件持续交互

stderr=subprocess.PIPE改成stderr=subprocess.STDOUT，则错误输出和正常输出一样

    def start(self):
        exepath = "d:/test.exe"
        command = "--file abc.txt"
        args = exepath + " " + command
        p = subprocess.Popen(args, stdin=subprocess.PIPE,
                            stdout=subprocess.PIPE, stderr=subprocess.PIPE, universal_newlines=True, shell=True)

        p.stdin.write('version\n') #需要加上\n
        p.stdin.flush() #write完后，需要flush

        while True:
            line = p.stdout.readline()
            if line != "":
                print(line)

                #持续交互
                p.stdin.write('version\n') #需要加上\n
                p.stdin.flush() #write完后，需要flush