原题网址:https://leetcode.com/problems/flip-game-ii/
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.
Write a function to determine if the starting player can guarantee a win.
For example, given s = "++++", return true. The starting player can guarantee a win by flipping the middle "++" to become "+--+".
Follow up:
Derive your algorithm's runtime complexity.
方法:MinMax算法,深度优先搜索
public class Solution {
private boolean canWin(char[] sa) {
for(int i=0; i<sa.length-1; i++) {
if (sa[i]=='+' && sa[i+1]=='+') {
sa[i]='-';
sa[i+1]='-';
boolean otherCanWin = canWin(sa);
sa[i]='+';
sa[i+1]='+';
if (!otherCanWin) return true;
}
}
return false;
}
public boolean canWin(String s) {
return canWin(s.toCharArray());
}
}
这道题有个很牛的算法,我没看懂。。。
参考:
https://leetcode.com/discuss/64344/theory-matters-from-backtracking-128ms-to-dp-0ms

本文探讨了LeetCode上Flip Game II的问题解决方法,通过MinMax算法及深度优先搜索策略,帮助玩家确定是否能确保赢得游戏。文章提供了详细的代码实现。
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