原题网址:https://leetcode.com/problems/flip-game-ii/
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: +
and -
, you and your friend take turns to flip twoconsecutive "++"
into "--"
. The game ends when a person can no longer make a move and therefore the other person will be the winner.
Write a function to determine if the starting player can guarantee a win.
For example, given s = "++++"
, return true. The starting player can guarantee a win by flipping the middle "++"
to become "+--+"
.
Follow up:
Derive your algorithm's runtime complexity.
方法:MinMax算法,深度优先搜索
public class Solution {
private boolean canWin(char[] sa) {
for(int i=0; i<sa.length-1; i++) {
if (sa[i]=='+' && sa[i+1]=='+') {
sa[i]='-';
sa[i+1]='-';
boolean otherCanWin = canWin(sa);
sa[i]='+';
sa[i+1]='+';
if (!otherCanWin) return true;
}
}
return false;
}
public boolean canWin(String s) {
return canWin(s.toCharArray());
}
}
这道题有个很牛的算法,我没看懂。。。
参考:
https://leetcode.com/discuss/64344/theory-matters-from-backtracking-128ms-to-dp-0ms