Ithea Plays With Chtholly （模拟）

Ithea Plays With Chtholly

This is an interactive problem. Refer to the Interaction section below for better understanding.

Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.

Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.

This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).

Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.

Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.

Input

The first line contains 3 integers n, m and c (, means rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.

Interaction

In each round, your program needs to read one line containing a single integer p_i (1 ≤ p_i ≤ c), indicating the number given to Chtholly.

Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.

After outputting each line, don't forget to flush the output. For example:

• fflush(stdout) in C/C++;
• System.out.flush() in Java;
• sys.stdout.flush() in Python;
• flush(output) in Pascal;
• See the documentation for other languages.

If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.

Example

Input

2 4 4
2
1
3

Output

1
2
2

Note

In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.

Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.

The input format for hacking:

• The first line contains 3 integers n, m and c;
• The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round.

如果给的数小于等于c/2正着遍历板子，如果找到有大于这个数的替换否则到空位置放上，如果给的数大于c/2，倒着遍历板子

如果找到小于这个数的板子替换，否则找到第一个空板子放上。每次检查n个板子是否满了

code:

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int n,m,c;
int sheet[1002];
int main(){
    scanf("%d%d%d",&n,&m,&c);
    while(m--){
        int x;
        scanf("%d",&x);
        int cnt = 0;
        if(x * 2 <= c){
            for(int i = 1; i <= n; i++){
                if(sheet[i] > x){
                    sheet[i] = x;
                    printf("%d\n",i);
                    break;
                }
                if(!sheet[i]){
                    sheet[i] = x;
                    cnt++;
                    printf("%d\n",i);
                    break;
                }
            }
        }
        else{
            for(int i = n; i >= 1; i--){
                if(sheet[i] < x){
                    sheet[i] = x;
                    printf("%d\n",i);
                    break;
                }
                if(!sheet[i]){
                    sheet[i] = x;
                    cnt++;
                    printf("%d\n",i);
                    break;
                }
            }
        }

        fflush(stdout);
        if(cnt == n) break;
    }
    return 0;
}