题目链接:Codeforces 19A World Football Cup
题意:有
n
支队伍打
一、按总分;
二、按进球数 - 被进球数;
三、按进球数;
均按降序。
最后按字典序输出前
AC 代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <vector>
#include <queue>
#include <map>
#include <stack>
#define PI acos(-1.0)
#define CLR(a, b) memset(a, (b), sizeof(a))
#define fi first
#define se second
#define ll o<<1
#define rr o<<1|1
using namespace std;
typedef long long LL;
typedef pair<int, int> pii;
const int MAXN = 50*50+10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
void getmax(int &a, int b) {a = max(a, b); }
void getmin(int &a, int b) {a = min(a, b); }
void add(LL &x, LL y) { x += y; x %= MOD; }
struct Node {
string name;
int total;
int win, loss;
};
Node num[MAXN];
bool cmp(Node a, Node b) {
if(a.total != b.total) return a.total > b.total;
if(a.win - a.loss != b.win - b.loss)
return a.win - a.loss > b.win - b.loss;
return a.win > b.win;
}
map<string, int> fp;
string winner[MAXN];
int main()
{
int n; cin >> n; fp.clear();
for(int i = 1; i <= n; i++) {
cin >> num[i].name;
fp[num[i].name] = i;
num[i].total = num[i].win = num[i].loss = 0;
}
for(int i = 1; i <= n * (n-1) / 2; i++)
{
string a, b;
cin >> a >> b;
string team1, team2;
team1 = team2 = "";
int score1, score2;
score1 = score2 = 0;
int j = 0;
for(; j < a.size(); j++) {
if(a[j] == '-') break;
team1 += a[j];
}
j++;
for(; j < a.size(); j++)
team2 += a[j];
j = 0;
for(; j < b.size(); j++) {
if(b[j] == ':') break;
score1 = score1 * 10 + (b[j] - '0');
}
j++;
for(; j < b.size(); j++)
score2 = score2 * 10 + (b[j] - '0');
//cout << team1 << score1 << team2 << score2 << endl;
int s = fp[team1];
int t = fp[team2];
int snum, tnum;
if(score1 > score2) {
snum = 3;
tnum = 0;
}
else if(score1 < score2) {
snum = 0;
tnum = 3;
}
else snum = tnum = 1;
num[s].total += snum;
num[t].total += tnum;
num[s].win += score1;
num[s].loss += score2;
num[t].win += score2;
num[t].loss += score1;
}
sort(num+1, num+n+1, cmp);
for(int i = 1; i <= n/2; i++) {
winner[i] = "";
winner[i] += num[i].name;
}
sort(winner+1, winner+n/2+1);
for(int i = 1; i <= n / 2; i++)
cout << winner[i] << endl;
return 0;
}