1058 A+B in Hogwarts -PAT甲级

最新推荐文章于 2020-04-20 11:32:33 发布

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本文介绍了一种基于哈利波特魔法世界货币系统的计算方法，通过处理不同单位间的转换，实现两个货币值的加法运算。输入为两个标准形式的货币值，输出为它们的和，同样以标准形式表示。

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题目描述

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough."  Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

输入描述:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

输出描述:

For each test case you should output the sum of A and B in one line, with the same format as the input.

输入例子:

3.2.1 10.16.27

输出例子:

14.1.28

稍微处理一下进制即可

#include<bits/stdc++.h>
using namespace std;
int main(){
	int g[3],s[3],k[3];
	scanf("%d.%d.%d",&g[0],&s[0],&k[0]);
	scanf("%d.%d.%d",&g[1],&s[1],&k[1]);
	k[2]=(k[0]+k[1])%29;
	s[2]=((k[0]+k[1])/29+s[0]+s[1])%17;
	g[2]=((k[0]+k[1])/29+s[0]+s[1])/17+g[0]+g[1];
	printf("%d.%d.%d\n",g[2],s[2],k[2]);
	return 0;
}