C - u Calculate e

   A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

Output Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output

n e
- -----------
0 1
1 2
2 2.5
3 2.666666667

4 2.708333333

#include<iostream>

#include<stdlib.h>

#include<cmath>

#include<cstring>

using namespace std;

long long mi(int l){

if(l==0) 

 return 1;

long long num=1;

for(int i=1;i<=l;i++)

{

num=num*i;

}

return num;

}

int main(){

double e=0

;cout<<"n e"<<endl;

cout<<"- -----------"<<endl;

for(int i=0;i<=2;i++) {

e=e+1.0/mi(i);

cout<<i<<" "<<e<<endl; 

}

for(int i=3;i<=9;i++)

{

e=e+1.0/mi(i);

printf("%d %.9lf\n",i,e); 

}

return 0;

}