621 - Secret Research

实验结果解密

最新推荐文章于 2024-06-19 19:30:00 发布

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本文介绍了一个简单的字符串处理问题，通过对比特定的字符串模式来解密实验结果，包括正向、负向、失败或未完成等状态。

Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:



positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):


		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*

就是道简单的字符串处理题。。一开始数组开小了。RE了。

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
    int t,len;
    cin>>t;
    getchar();
    while(t--)
    {
        char str[10000];
        gets(str);
        len=strlen(str);
        if (strcmp(str,"1")==0 || strcmp(str,"4")==0 || strcmp(str,"78")==0) cout<<"+"<<endl;
        else if (strcmp(str+len-2,"35")==0) cout<<"-"<<endl;
        else if (str[0]=='9' && str[len-1]=='4') cout<<"*"<<endl;
        else if (str[0]=='1' && str[1]=='9' && str[2]=='0') cout<<"?"<<endl;
        else cout<<endl;
    }
    return 0;
}