1005 Spell It Right（sstream / to_string()）

最新推荐文章于 2020-09-03 14:20:55 发布

原创最新推荐文章于 2020-09-03 14:20:55 发布 · 216 阅读

0 ·

CC 4.0 BY-SA版权

PAT甲级专栏收录该内容

22 篇文章

订阅专栏

本文详细解析了一个将非负整数的各位数字之和转换为英文单词表示的算法。通过将整数转换为字符串，遍历字符串计算数字之和，并最终将这个和再次转换为英文单词形式输出。此算法适用于不超过10^100的大整数。

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (≤10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

Analyze:

Just learn how to convert an integer to a string. Except this, nothing need to say.

#include<iostream>
//#include<sstream>

using namespace std;

int main(){
	int sum = 0;
	string a[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
	string num, result;
	cin >> num;
	for(int i = 0; i < num.length(); i++) sum += num[i] - '0';
	result = to_string(sum);
	/*
	ostringstream os;
	os << sum;
	istringstream is(os.str());
	is >> result;
	*/
	for(int i = 0; i < result.length(); i++){
		if(i == 0) cout << a[result[i] - '0'];
		else cout << ' ' << a[result[i] - '0'];
	}
	return 0;
}