You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.
Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.
You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.
采用BinarySearch方法,但是对搜寻规则要做一些改变。
// Forward declaration of isBadVersion API.
bool isBadVersion(int version);
class Solution {
public:
int firstBadVersion(int n) {
int start = 0, end = n;
n = start + (end - start) / 2;
while (start != end) {
if (isBadVersion(n))
end = n;
else
start = n + 1;
n = start + (end - start)/2;
}
return start;
}
};
本文介绍了一种改进的二分查找方法,用于确定产品版本中首次出现不良版本的位置,以减少调用API的次数。通过实例演示算法实现,并解释其在软件开发过程中的应用。

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