PAT 1058. A+B in Hogwarts

最新推荐文章于 2022-05-05 19:26:29 发布

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最新推荐文章于 2022-05-05 19:26:29 发布

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本文链接：https://blog.youkuaiyun.com/zjucor/article/details/52802200

本文介绍了一个基于Harry Potter魔法世界货币系统的加法程序。该程序使用C语言实现，能够处理Galleon、Sickle和Knut三种单位的加法运算，并通过scanf函数读取输入。

只想说scanf的强大

1058. A+B in Hogwarts (20)

时间限制

50 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

#include <cstdio>

using namespace std;

int a1, b1, c1, a2, b2, c2;

int main()
{
    scanf("%d.%d.%d %d.%d.%d", &a1, &b1, &c1, &a2, &b2, &c2);
    int a, b , c;
    c = (c1 + c2) % 29;
    b = ((c1 + c2) / 29 + b1 + b2) % 17;
    a = ((c1 + c2) / 29 + b1 + b2) / 17 + a1 + a2;

    printf("%d.%d.%d", a, b, c);
    return 0;
}