1058 A+B in Hogwarts（20 分）（C++）_a+b in hogwarts c++-优快云博客

本文链接：https://blog.youkuaiyun.com/qq_41562704/article/details/82215505

博客围绕编写程序计算特殊进制数相加展开。给定的数分为三部分，从右往左，第一部分是29进制，第二部分是17进制。介绍了输入规范、输出规范，还给出了示例输入和输出，要求按特定格式输出两数相加结果。

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If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题目大意：一个数分为三部分，从右往左，第一部分数29进制，第二部分数为17进制。计算两个数相加

#include<cstdio>
using namespace std;
int main()
{
    int a1,b1,c1,a2,b2,c2;
    scanf("%d.%d.%d %d.%d.%d",&a1,&b1,&c1,&a2,&b2,&c2);
    int c=(c1+c2)%29;
    int b=(b1+b2+(c1+c2)/29)%17;
    int a=(b1+b2+(c1+c2)/29)/17+a1+a2;
    printf("%d.%d.%d",a,b,c);
    return 0;
}