A+B in Hogwarts（进位加法）

最新推荐文章于 2021-08-05 11:13:49 发布

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本文介绍了一道关于哈利波特世界中货币系统计算的题目。该货币系统由Galleon、Sickle和Knut组成，遵循特定的进制规则。文章提供了一个简单的C++程序来计算两个货币值的总和，并展示了输入输出示例。

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1058. A+B in Hogwarts
If you are a fan of HarryPotter, you would know the world of magic has its own currency system -- asHagrid explained it to Harry, "Seventeen silver Sickles to a Galleon andtwenty-nine Knuts to a Sickle, it's easy enough." Your job is to write aprogram to compute A+B where A and B are given in the standard form of"Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷],Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
InputSpecification:
Each input file contains one test case which occupies aline with A and B in the standard form, separated by one space.
OutputSpecification:
For each test case you should output the sum of A and B inone line, with the same format as the input.
Sample Input:
3.2.1 10.16.27

Sample Output:

14.1.28

题意：给出两组数，按位相加，后两位分别满17，29进1，求和。

PAT水题

AC代码：

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
using namespace std;

int main()
{
	int a1, a2, a3, b1, b2, b3, c1, c2, c3;
	scanf("%d.%d.%d %d.%d.%d", &a1, &a2, &a3, &b1, &b2, &b3);
	int jin = 0;
	if(a3 + b3 >= 29)
		jin = 1;
	c3 = (a3 + b3) % 29;
	if(a2 + b2 + jin >= 17)
	{
		c2 = (a2 + b2 + jin) % 17;
		jin = 1;
	}
	else
	{
		c2 = a2 + b2 + jin;
		jin = 0;
	}
	c1 = a1 + b1 + jin;
	printf("%d.%d.%d\n", c1, c2, c3);
	return 0;
}