该函数在一个字符串中找到可能的最长的子字符串,

本文介绍了一段 C# 代码,该代码用于找出输入字符串中出现的所有最长连续重复字符序列,并将这些序列以字符串数组的形式返回。示例代码演示了如何通过遍历和比较来确定最长序列。

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如题,输出可能有多个最长字符串。

 

C# codes as below,

 

class Program

    {

        static void Main(string[] args)

        {

            string[] str = GetMaxString("1223344555666555777788887777");

            foreach (string s in str)

            {

                Console.WriteLine(s);

            }

            Console.ReadKey();

        }

        static string[] GetMaxString(string str)

        {

            if (str == string.Empty || str == null)

            {

                return null;

            }

 

            //Set the default value of the string number is 1

            int stringNumber=1;

 

            //Set the default value of the string length is 1

            int stringLength = 1;

           

            char[] allChars = new char[str.Length];

            //Set the default value of the first element is str[0]

            allChars[0] = str[0];

 

            char currentChar=str[0];

            int count = 0;

 

            for (int i = 0; i < str.Length; i++)

            {

                if (str[i] == currentChar)

                {

                    count++;

                    if (count == stringLength)

                    {

                        //Set a bool mark to judge if the char has existed in the array allChars

                        bool ifExist = false;

                        //Go on a cycle to judge if the char has existed in the array allChars

                        for (int j = 0; j < stringNumber; j++)

                        {

                            if (allChars[j] == str[i])

                            {

                                ifExist = true;

                            }

                        }

                        //If this char hasn't been included in the array allChars, add it to the array.

                        if (!ifExist)

                        {

                            //Reset the number of the output strings

                            stringNumber++;

                            allChars[stringNumber - 1] = str[i];

                        }

                    }

                    else if (count > stringLength)

                    {

                        //Reset the number, length and value for the output strings

                        stringLength++;

                        stringNumber = 1;

                        allChars[0] = str[i];

                    }

                }

                else

                {

                    //Reset current char's value

                    currentChar = str[i];

                    //Reset the value of count

                    count = 0;

                    //Recycle

                    i--;

                }

            }

            //Name a string array

            string[] result = new string[stringNumber];

            //Set the value of the array

            for (int i = 0; i < stringNumber; i++)

            {

                result[i] = new string(allChars[i], stringLength);

            }

            return result;

        }

    }

 

output:

 

7777

8888

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