ACM与蓝桥杯竞赛指南 基本输入输出格式四

 A+B for Input-Output Practice (IV)

题目描述：

Your task is to Calculate the sum of some integers.

输入格式：

 Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.

输出格式：

For each group of input integers you should output their sum in one line, and with one line of output for each line in input. 

样例输入： 

4 1 2 3 4 
5 1 2 3 4 5 
0

 样例输出：

10 
15

想必结合题意和样例，大家已经明白题目考察点了，就是累加求和，只不过个数n需要提前指定，为0表示结束，故而我们可以先接收n并且判断n非0再进入循环，循环n次累加求和

参考C语言代码：

#include<stdio.h>
int main()
{
  int n;
  int sum,temp;
  while(scanf("%d",&n) && n)
  {
      sum=0;
      while(n--)
      {
          scanf("%d",&temp);
              sum+=temp;
      }
      printf("%d\n",sum);
  }
  return 0;
}

注意本题，为双重循环，每次累加求和的sum一定要每次都要归零！这是一个易错点

参考C++写法：

#include<iostream>
using namespace std;
int main()
{
    int n,x;
    while(cin>>n && n)
    {
      int sum=0;
      while(n--)
      {
        cin>>x;
        sum+=x;
      }
      cout<<sum<<endl;
    }
    return  0;
}

参考Java代码：

import java.util.Scanner;
 
public class Main {
    public static void main(String[] args) {
 
        Scanner scanner = new Scanner(System.in);
        while (scanner.hasNext()) {
            int sum=0;
            int n = scanner.nextInt();
            if(n==0) 
                break;
            while (n--!=0){
                 int a=scanner.nextInt();
                 sum=sum+a;
            }
            System.out.println(sum);
             
        }
    }
}

参考Python代码：

while True: 
  sum=0 
  list=input().split()
  if list[0]=='0':
      break 
  for i in range(1,len(list)):
      list[i]=int(list[i])
      sum+=list[i]
  print(sum)