ACM与蓝桥杯竞赛指南 基本输入输出格式八

A+B for Input-Output Practice

题目描述：

Your task is to calculate the sum of some integers

输入格式:

Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line 

输出格式:

For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs. 

最后一个例题，和之前也看起来差不多，还是多个数字求和，不同的是在输出格式要求多一个空行，如输入：

3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3

输出：

10
 
15
 
6

参考C语言代码：

#include<stdio.h>
int main()
{
    int N,M;
    int a,sum;
    scanf("%d",&N);
    while(N--)
    {
        scanf("%d",&M);
        sum=0;
        while(M--)
        {
            scanf("%d",&a);
            sum=sum+a;
        }
        printf("%d\n\n",sum);
    }
}

参考C++代码：

#include<iostream>
using namespace std;
int main()
{
    int N,M;
    int a,sum;
    cin>>N;
    while(N--)
    {
        cin>>M;
        sum=0;
        while(M--)
        {
            cin>>a;
            sum=sum+a;
        }
        cout<<sum<<endl<<endl;
    }
}

参考Java代码：

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int N=sc.nextInt();
        while(N--!=0)
        {
            int M=sc.nextInt();
            int sum=0;
            while(M--!=0)
            {
                sum=sum+sc.nextInt();
            }
            System.out.println(sum);
            System.out.println();
        }
    }
}

 参考Python代码：

n = int(input()) 
for i in range(n): 
    sum=0    
    list=input().split()
    if list[0]=='0':
           break   
    for i in range(1,len(list)):
        list[i]=int(list[i])
        sum+=list[i]
    print(sum)
    print();

 以上就是本期内容 基本输入输出也迎来了完结