题目链接:https://leetcode.com/problems/insert-delete-getrandom-o1/?tab=Description
Design a data structure that supports all following operations in average O(1) time.
insert(val)
: Inserts an item val to the set if not already present.remove(val)
: Removes an item val from the set if present.getRandom
: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set. RandomizedSet randomSet = new RandomizedSet(); // Inserts 1 to the set. Returns true as 1 was inserted successfully. randomSet.insert(1); // Returns false as 2 does not exist in the set. randomSet.remove(2); // Inserts 2 to the set, returns true. Set now contains [1,2]. randomSet.insert(2); // getRandom should return either 1 or 2 randomly. randomSet.getRandom(); // Removes 1 from the set, returns true. Set now contains [2]. randomSet.remove(1); // 2 was already in the set, so return false. randomSet.insert(2); // Since 2 is the only number in the set, getRandom always return 2. randomSet.getRandom();
解题思路:初始化一个unordered_map和一个vector,unordered_map记录要插入元素在vector中的位置,删除元素时,把要删除的元素与vector最后一位元素进行交换,再删除最后一位元素。
class RandomizedSet{
public:
RandomizedSet()
{
}
bool insert(int val)
{
if(map.count(val)!=0) return false;
map[val]=vec.size();
vec.push_back(val);
return true;
}
bool remove(int val)
{
if(map.count(val)==0) return false;
int pos=map[val];
map[vec.back()]=pos;
swap(vec[pos],vec[vec.size()-1]);
map.erase(val);
vec.pop_back();
return true;
}
int getRandom()
{
return vec[rand()%vec.size()];
}
private:
unordered_map<int,int> map;
vector<int> vec;
};