TensorFlow报错FutureWarning: Passing (type, 1) or ‘1type‘ as a synonym of type is deprecated

最新推荐文章于 2022-05-13 13:30:48 发布

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最新推荐文章于 2022-05-13 13:30:48 发布

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文章标签： tensorflow

本文链接：https://blog.youkuaiyun.com/wuwuzijie/article/details/108844828

本文介绍了一种因numpy版本过高导致的问题及其解决方案。当使用过高的numpy版本时可能会遇到错误，解决办法是回退到numpy-1.16-0版本。

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报错原因：numpy版本过高，使用numpy-1.16-0版本即可

解决方法：重新安装numpy-1.16-0

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(tensorflow1.3) C:\Users\AH>python Python 3.6.2 |Continuum Analytics, Inc.| (default, Jul 20 2017, 12:30:02) [MSC v.1900 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import tensorflow as tf D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:458: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint8 = np.dtype([("qint8", np.int8, 1)]) D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:459: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_quint8 = np.dtype([("quint8", np.uint8, 1)]) D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:460: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint16 = np.dtype([("qint16", np.int16, 1)]) D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:461: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_quint16 = np.dtype([("quint16", np.uint16, 1)]) D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:462: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint32 = np.dtype([("qint32", np.int32, 1)]) D:\Anaconda3\envs\tensorflow1.3\lib\site-packages\tensorflow\python\framework\dtypes.py:465: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. np_resource = np.dtype([("resource", np.ubyte, 1)]) 以上情况，是不是没问题？