PAT 1031

按格式输出,注意条件

#include<iostream>
#include<string>
#include<algorithm>
#include<string.h>
using namespace std;
#define MAX 100005

int main() {
	char str[MAX];
	scanf("%s", str);
	int len = strlen(str);
	int n1, n2, n3;
	if (len % 3 == 0)
		n1 = n3 = len  / 3;
	else
	n1 = n3 = (int)((len+2) / 3.0 + 0.5) > (int)(len + 2) / 3.0 ? (int)(len + 2) / 3.0 + 1 : (int)(len + 2) / 3.0;
	n2 = len + 2 - n1 - n3;
	int begin = 0,end=len-1;
	while (n1) {
		printf("%c", str[begin]);
		for (int i = 0; i < n2 - 2; i++) {
			printf(" ");
		}
		printf("%c\n", str[end]);
		begin++, end--;
		n1--, n3--;
		if (n1 == 1) {
			for (int i = begin; i <= end; i++) {
				printf("%c", str[i]);
			}
			printf("\n");
			n1--;
		}


	}
	return 0;
}