PAT_甲级_1031

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最新推荐文章于 2021-08-27 21:21:31 发布

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本文解析了一道编程题“1031HelloWorldforU”，题目要求将任意长度大于等于5的字符串，按照特定的U形布局进行打印。详细介绍了输入输出规格，并提供了一个C++实现示例，展示了如何根据字符串长度计算U形布局的尺寸，以及如何按要求打印字符串。

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1031 Hello World for U

Given any string of N (≥5) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as:

h　　d
e　　l
l　　 r
l o w o
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n1 =n3 =max { k | k≤n2 for all 3≤n2 ≤N } with n1 +n2 +n3 −2=N.

Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:
For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h !
e d
l l
lowor

#include<iostream>
#include<stdio.h>
#include<string.h>
#include<vector>
#include<string>
using namespace std;
char arr[100];
int main()
{
    cin >> arr;
    int len = strlen(arr);
    int n1_len, n2_len;
    for (n2_len = 3; n2_len <= len; n2_len++) {
        if ((len - n2_len) % 2 == 1) continue;
        n1_len = (len - n2_len + 2) / 2;
        if (n1_len <= n2_len) break;
    }
    for (int i = 0; i < n1_len - 1; i++) {
        cout << arr[i];
        for (int j = 0; j < n2_len - 2; j++) {
            cout << ' ';
        }
        cout << arr[len - 1 - i] << endl;
    }
    for (int i = 0; i < n2_len; i++) {
        cout << arr[n1_len - 1 + i];
    }
    return 0;
}