1077 Kuchiguse(字符串处理)

此博客介绍了一道编程题目,旨在通过分析角色对话的共同后缀来识别其个性特征(Kuchiguse)。利用C++实现,通过逐行对比输入的多条对话,找出最长的共同结尾词,展示了一个有趣且实用的字符串处理技巧。

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1077 Kuchiguse (20 分)

The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker’s personality. Such a preference is called “Kuchiguse” and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle “nyan~” is often used as a stereotype for characters with a cat-like personality:

  • Itai nyan~ (It hurts, nyan~)

  • Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

Input Specification:

Each input file contains one test case. For each case, the first line is an integer N (2≤N≤100). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character’s spoken line. The spoken lines are case sensitive.

Output Specification:

For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write nai.

Sample Input 1:
3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~

Sample Output 1:

nyan~

Sample Input 2:

3
Itai!
Ninjinnwaiyada T_T
T_T

Sample Output 2:

nai
分析

本题本质是求给定的多个字符串的共同后缀。

#include <iostream>
#include <algorithm>
using namespace std;
int main(){
	int n;
	string s1;
	cin>>n;
	getchar();
	getline(cin,s1);
	for(int k=1;k<n;k++){
		string s2;
		getline(cin,s2);
		int i=s1.length()-1,j=s2.length()-1;
		string tmp;
		while(i>=0 && j>=0){
			if(s1[i]==s2[j]) tmp.push_back(s1[i]);
			else break;
			i--,j--;
		}
		s1=tmp;
		reverse(s1.begin(), s1.end());
	}
	if(s1.length()!=0) cout<<s1<<endl;
	else cout<<"nai"<<endl;
	return 0;
}
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