『杭电1560』DNA sequence

最新推荐文章于 2021-08-06 22:06:03 发布
最新推荐文章于 2021-08-06 22:06:03 发布
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分类专栏： # 杭电题库 文章标签： 算法 c++
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这是一道关于生物学和计算机科学交叉的问题。任务是给定一些DNA序列，找到一个最短的序列，使得所有给定的序列都是其子序列。例如，给定序列'ACGT', 'ATGC', 'CGTT' 和 'CAGT'，可以得到一个长度为8的最短序列。输入包含测试用例数t和每个测试用例的DNA序列数量n，输出是最短序列的长度。" 117521025,10553358,凤凰OS 3.0.5版Android x86系统root详细教程,"['Android开发', '系统优化', 'root教程', '凤凰OS', 'x86']

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Problem Description

The twenty-first century is a biology-technology developing century. We know that a gene is made of DNA. The nucleotide bases from which DNA is built are A(adenine), C(cytosine), G(guanine), and T(thymine). Finding the longest common subsequence between DNA/Protein sequences is one of the basic problems in modern computational molecular biology. But this problem is a little different. Given several DNA sequences, you are asked to make a shortest sequence from them so that each of the given sequence is the subsequence of it.

For example, given "ACGT","ATGC","CGTT" and "CAGT", you can make a sequence in the following way. It is the shortest but may be not the only o

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