hdu 1002 A + B Problem II_sample input 2 1 2 112233445566778899 998877665544-优快云博客

本文链接：https://blog.youkuaiyun.com/weixin_41380961/article/details/83548190

本文介绍了一个关于大数加法的编程挑战，使用Java的BigInteger类来处理超过32位整数的运算，确保了计算的准确性。示例代码展示了如何读取输入，进行大数加法，并按照指定格式输出结果。

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I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

java写法:

import java.util.*;
import java.math.*;
public class Main
{
	public static void main(String[] args)
	{
		int t;
		Scanner in=new Scanner(System.in);
		for(int i=1;i<=t;i++)
		{
			BigInteger a,b;
			a=in.nextBigInteger();
			b=in.nextBigInteger();
			System.out.println("Case "+i+":");
			System.out.println(a+" + "+b+" = "+a.add(b));
			if(i!=t)
				System.out.println();
		}
	}
}