提交Link: http://wikioi.com/problem/1154/
状态:dp[i][j] 表示第【i,j】的最优结果
状态转移: dp[i][j] = max(dp[i][k]+dp[k+1][j]+cost)
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
#define MAXN 111
#define INF 0x7fffffff
typedef struct NODE_ {
int l, r;
}NODE;
NODE val[MAXN], ori[MAXN];
int dp[MAXN][MAXN], tmp[MAXN];
void conversion(const int &idx, const int &n)
{
int index(0);
for(int i = idx; i < n; i ++) {
val[index ++] = ori[i];
}
for(int i = 0; i < idx; i ++) {
val[index ++] = ori[i];
}
}
int dfs(const int &l, const int &r)
{
if( l >= r ) {
return 0;
}
if( -1 != dp[l][r] ) {
return dp[l][r];
}
int rst(0);
for(int k = l; k < r; k ++) {
rst = max(rst, dfs(l, k)+dfs(k+1, r)+val[l].l*val[k].r*val[r].r);
}
return dp[l][r] = rst;
}
int main(int argc, char const *argv[])
{
#ifndef ONLINE_JUDGE
freopen("test.in", "r", stdin);
#endif
int n, idx, rst;
scanf("%d", &n);
for(int i = 0; i < n; i ++) {
scanf("%d", &tmp[i]);
}
rst = 0; idx = 0;
for(int i = 0; i < n-1; i ++) {
ori[idx].l = tmp[i]; ori[idx ++].r = tmp[i+1];
}
ori[idx].l = tmp[n-1]; ori[idx].r = tmp[0];
for(int i = 0; i < n; i ++) {
conversion(i, n); memset(dp, -1, sizeof(dp)); rst = max(rst, dfs(0, n-1));
}
printf("%d\n", rst);
return 0;
}