UVa 10071 Back to High School Physics (water ver.)

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于 2013-09-13 10:24:04 发布

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分类专栏： UVa acm之路--数学文章标签： acm c++ UVa

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本文探讨了一个关于物理问题的数学模型，并通过编程解决实际问题。具体来说，文章介绍了如何利用给定的初始速度和恒定加速度，计算粒子在特定时间后的位移，并在双倍时间内进行求解。通过实例输入输出展示了算法的应用过程。

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10071 - Back to High School Physics

Time limit: 3.000 seconds

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94&page=show_problem&problem=1012

A particle has initial velocity and constant acceleration. If its velocity after certain time is v then what will its displacement be in twice of that time?

Input

The input will contain two integers in each line. Each line makes one set of input. These two integers denote the value of v (-100 <= v <= 100) and t(0<=t<= 200) ( t means at the time the particle gains that velocity)

Output

For each line of input print a single integer in one line denoting the displacement in double of that time.

Sample Input

0 0
5 12

Sample Output

0
120

/*0.029s*/

#include <cstdio>

int main(void)
{
	int v, t;
	while (~scanf("%d%d", &v, &t))
		printf("%d\n", v * t << 1);
	return 0;
}